\fPart F Determine the moment at point D. Express your answer to three significant figures and include the appropriate units. HA MD = 606 1b Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Enter your answer with a different unit type. Review a list of acceptable units.Part C Determine the moment at point C. Express your answer to three significant figures and include the appropriate units. ULA Xb x . 10n X Mc = 1852 1b Enter your answer with a different unit type. Review a list of acceptable units. No credit lost. Try again.Given that F1 = 513 16 F2 = 192 16 513 16 192 lb 303 16 B F3 2 303 16 . A . 6ft 4 H @ # 65+ D RHE RX Re IFy = 0. 7 RATRB = 513+ 192+ 303 = 1008 Pb . -0 From equilibrium of moment about B- EMO = 0 - RA X 14 + 303 x8 = 513x 8 2 RX = 120 lb so , from egu O we get RB = 1008 - 120 .: RB = 888 lb . Part A: Internal normal force at point C, Ne = O ( net force in x direction = 0 ). Part B: The shave force at point c, Vc = RA - 513 = - 393 16 - 393 16 Thus share force acts in vertically upward direction .Part C : The moment at point c, Mc = RA X 10 - 513 x4 = (120*10) -(513x4) .: Mc = - 852 1b. ft The negative sign indicates the moment is in clockwise direction. Part D: The internal normal force at point . D, ND 20 Pam- - E : The shean force at fromt D, VD = F3 = 303 16. The direction of force is vertically upward. Parrot - F : The moment at point D, MD = - F3 (DE ) 27 MD = - 2F3 =-2x 303 Pbift MD = - 606 16. ft The direction of the moment is opposite to that considered in the diagram . so, the moment at D iS in counterclockwise direction