G = 6.67259 x 10-11 (Nom2)/kg2 Earth Mass.............. ................... 5.98 X 10^24 kg Sun Mass.................. 1.99 X 10^30 kg Radius of Earth............ .......................6.38 X 10^6 m Radius of Sun................6.96 X 10^8 m What is the force of attraction between a 60.0 kg student in the senior parking lot and the school? The distance between the two is 100.000 m and the mass of the school 65,000,000 kg. The Hubble Telescope orbits the Earth 596,000 m ABOVE THE SURFACE of the earth. What is the Telescope's Period? Analyze this: A 80.3-N force is applied at an angle of 20.8 above the horizontal to accelerate a 7.59-kg object across a level surface. The object encounters 15.1 N of friction. Complete the diagram. Tap on a field to enter or edit its value Fnorm Fapp = = Firlot Fx Fx = Fy = Fgrav Units Force: N m= Mass: kg Accel'n: m/s/s