Gabbie Alfaro 02/21/24 10:09 AM Question 2 of 4 This quiz: 4 point(s) possible This question: 1 point(s) possible Submit quiz A genetic experiment involving peas yielded one sample of offspring consisting of 417 green peas and 121 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. vvnat are the null and alternative nypotheses? OA. Ho: p 0.26 H: p 0.26 What is the test statistic? N= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? OB. Ho: p=0.26 H: p# 0.26 OD. Ho: p=0.26 H: p 0.26 OA. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. OD. Reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? OA. There is not sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. OB. There is sufficient evidence to support the claim that less than 26% of offspring peas will be yellow. OC. There is sufficient evidence to warrant rejection of the claim that 26% of offspring peas will be yellow. 80 F3 000 F4 F5 MacBook Air F6 F9 F10 DII DD F7 F8 $ % 3 4 5 6 7 29 & * ( 8 9 0 E R T Y U I 0 Next (1)) F11 F12 + || } P [ J