Question: Consider the following MIPS program segment and the contents of the memory contents (in hexadecimal) shown below. What is the content of memory address

Consider the following MIPS program segment and the contents of the memory contents (in hexadecimal) shown below. What is the content of memory address

Consider the following MIPS program segment and the contents of the memory contents (in hexadecimal) shown below. What is the content of memory address (10004) after we executed the program? Address Hex. Contents ........ (before execution) 12345678 87654321 li $7, 1 10000 addi $8, $0, 3 li $9, 10000 Iw $10, 0 ($9) 10004 10008 00000001 2: 10012 00000002 andi $11, $10, 1 00000003 11111110 22222220 33333330 10016 beq $11, $0, L1 sll $10, $10, 4 sw $10, 0 ($9) addi $9, $9, 4 10020 10024 10028 10032 10036 44444440 55555550 addi $7, $7, 1 bne $7, S8, L2 J Exit 1: sl $10, S10, 4 sw $10, 0 ($9) addi $9, $9, 4 addi S7. S7, 1 bne $7. S8, L2 e English (en) register-file rregi Sregi i Srt rreg2 Sreg2 Memory ALU address data or Instr. wreg wdata Srt data sign- shift- Imm extend left-2 Target 1. shift- lmm loft-2 Assume that or $1, $2, $3 instruction is executed on this datapath. The contents of PC when or is being executed is (36)10. What will be the contents of target register at the end of 2nd clock cycle? one: (105)10 (44)10 (100)10 (40) 10 Next page ALUResuit Instruction Register ALUResult TargetWrte

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