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Given System 1: 5x-2y +4z = 0 2x-3y+5z = 8 3x+4y-3z = -11 System 2: 3x - 2y + z = 24 2x +

Given System 1: 5x-2y +4z = 0 2x-3y+5z = 8 3x+4y-3z = -11 System 2: 3x - 2y + z = 24 2x + 2y + 2z = 12 x+5y-2z-31 i) By using inverse matrix method, find x, y, and z for System 1 and System 2.

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