Question: Hello All! I'm currently working on a packet tracer practice and I've completed a good portion of it, however I'm stuck on this part of
Hello All! I'm currently working on a packet tracer practice and I've completed a good portion of it, however I'm stuck on this part of redoing the network and I have no Idea what to do next. How do I make new subnets for the IP addresses to put into each one? 

PC-17 2960-2AJT PC3-marcar2685 S3-marcar2685 2960-24TT PC-PT SA-marcar2685 PC4-marcar 2685 ISR4321 R2-marcar2685 JSR4321 RX-marcar2685 2960-24TT 2960-24TT PC-PT PC-PT PC1-marcar2685 S2-marcar 2685 PC2-marcar2685 S1-marcar2685 k) You are assigned the 192.168._40_.0/24 network, where_40_ is assigned by your instructor. Subnet this network so that you have enough subnets for all the networks you have created 1) Document your work: i) You are going to redo the subnets from week 1 so you'll need to reprogram both your R1 and R2 routers. ii) Record the network number and subnet mask for each subnet in the guided practice report. Remember, these all need to be from the 192.168._40_.0/24 network. You| will need to replace the ___ symbol with the correct network or subnet mask number. Router Network number Subnet Mask R1 Executive 40.0 255.255.255.### R1 Administrative 192.168. 255.255.255.### R2 HelpDesk 40_.48 R2 Engineering 40 .80 255.255.255.### Ser R1-R2 192.168. 40.200 users 20 192.168. 40 .32 10 255.255.255.### 20 192.168. 192.168. 10 255.255.255.252 2 ii) Using your table above, record the IP address and subnet mask you plan to use for each interface and host system in the guided practice report. Connection IP address Subnet Mask R1 GE 0/0/0 192.168._40_1 255.255.255.### R1 PC1 192.168. 40_2 255.255.255.### R1 GE 0/0/1 192.168. 40_.33 255.255.255.### R1 PC2 192.168. 40 .34 255.255.255.### R2 GE 0/0/0 192.168. 40 .49 255.255.255.### R2 PC3 192.168. 40.50 R2 GE 0/0/1 192.168._40 .81 R2 PC4 192.168._40 .82 Ser R1 SO/1/0 192.168._40_.201 Ser R2 S0/1/1 192.168. 40_.202 255.255.255.### 255.255.255.### 255.255.255.### 255.255.255.252 255.255.255.252
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To correctly subnet the given 19216840024 network you need to 1 Calculate the number of hosts required for each subnet 2 Determine the subnet mask nee... View full answer
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