Hello, I need help with solving a standard normal curve.

Thank you

The standard normal cunre: 1. Instructions: Using the z-tahle on the last page. nd the area under the standard normal curve for the given z-values. Find the area under the standard normal curve which lies: To the right of: = 2.1 the area is To the left ofz=-1.?, the area is . To the left of z = +1.?, the area is . [Careful here...use your headi To the right of z = -0.?, the area is . [Another tricky onel Between 2 = 1.2 and z = 1.?, the area is Between 2 = 419 and z = 4.3, the area is Between 2 = -1.4 and z = 1.4, the area is Between 2 = 40.9 and z = +1.6, the area is 2. W: Find the zvnlue when you are given a specied area under the curve. FirSt. look up in the ztabl'e {on the last page) the appropriate area in either column (B) or {C}, whichever is the correct column to help answer the question. Then move left on that row to nd the z-value in column (A). Adjust the sign afz, ifreauired. Find the z-values that yield the following areas under the normal curve: a. b. c. If an area of 0.455 is under the normal curve between 0 and +2, then 1 = If an area of 0.309 is under the normal curve to the right of 2, then 2 = If an area of 0.316 is under the normal curve to the right of 2, then 2 = {Remember that 0.5 of that area is coming 'orn the right half of the normal curve. so you only need to look up the balance. 0.316) If an area of 0.460 is under the normal curve to the left ofz, then I = . If an area of 0.?23 is under the normal curve between z and +1, then I = . (Hint: half of that area comes from the area between -z and 0, and the other half comes from the area between +1 and O.) . Instructions: Using the real normal data below, you'll first convert given x-values into z-scores. Then use the z-table below. You'll be given a z-value, and you'll look use the values in column (B) or (C) to answer the questions. The City of Colorado Springs performed many water tests on a certain day and determined that the bacteriological content of the water, as reported by the water tests, was normally disturbed with a mean of 10 ppm (parts per million) and a standard deviation of 1 ppm. a. Using this mean and standard deviation, transform 11.5 ppm to a z-score. Z = b. What is the probability that a measurement made on that day will have a bacteria count between 10 ppm and 11.5 ppm? Probability = area under the curve = _ C. What is the probability that a measurement made on that day will exceed 11.5 ppm? Probability = area under the curve = d. What is the probability that a measurement made on that day will be less than 8 ppm? Probability = area under the curve = Z-Score Table (A) (B) (C) (A) (B) (C) z-score Area between z Area beyond z-score Area between z Area beyond and the mean and the mean 0.0 0.000 0.500 1.6 0.44 0.055 0.1 0.040 0.460 1.7 0.455 0.045 0.2 0.079 0.421 1.8 0.464 0.036 0.3 0.118 0.382 1.9 0.471 0.029 0.4 0.155 0.345 2.0 0.477 0.023 0.5 0.192 0.30 2.1 0.482 0.018 0.6 0.226 0.274 2.2 0.486 0.014 0.7 0.258 0.242 2.3 0.489 0.011 0.8 0.288 0.212 2.4 0.492 0.008 0.9 0.316 0.184 2.5 0.494 0.006 1.0 0.341 0.159 2.6 0.495 0.005 1.1 0.364 0.136 2.7 0.496 0.004 1.2 0.385 0.115 2.8 0.497 0.003 1.3 0.403 0.097 2.9 0.498 0.002 1.4 0.419 0.081 3.0 0.499 0.001 1.5 0.433 0.067