Hello,

Please ONLY attempt if you intend to complete ALL of the following questions.

Thank you.

NR2 Determine the work done in braking a 1385 kg car from 16.9 mfs to a stop over a distance of 42.0m. Your newer needs to be in scientic notation as the x [0'1 and you record it on Canvas as abetl {do NOT use any decimals). Do NOT use a negative sign. even though the work is. NR3 Calculate the power of a 30.0 kg boy who runs up this ramp in 3.35 5. Record a 3-digit response. it my be a decimal. 642\": 510": USE THE FOLLOWING DIAGRAM TO ANSWER NR 7' mm Qf Hamm* block 131' wood = 1.50 kg I: -------------------- a new tibial!\" = 30.03 w=280llt Y v,=190u/s I2u3 5191 NR 7 What is the block's acceleration? Your answer needs to be in scientic notation as the x 10" and you record it on Canvas as shed (do NOT use any decimals). To allow EVERYONE the chance to get this right, you will assume that the average force exerted on the block was 6.45 x 10" N- USE THE FOLLOWING DIAGRAM TO ANSWER NR 10 An object starts from rest at a height of 5.00 m, and then slides off a frictionless ramp. When it leaves the ramp, it is at a height of 3.00 m and it has a horizontal velocity v. Vi = 0 5.00 m Vh = ? 3.00 m t = ? NR 10 Calculate the horizontal distance x, also known as the range. To allow EVERYONE the chance to get this right, you will assume that the horizontal velocity was 9.65 m/s A skier starts from rest at the top of a 20 incline and skis in a straight line to the bottom of the slope, a distance d (measured along the slope) of 400 m. If the coefficient of kinetic friction u between the skis and the snow is 0.20, calculate the skier's speed at the bottom of the run. [4 marks] You do not need the skier's mass to solve this problem. If you feel you must have it, then make it be 100 kg. There are TWO Ways to solve this: one involves the revised formula for conservation of energy that you learned in this unit, the other uses dynamics and kinematics. You can do it both ways, of course. I will give extra credit if you do (2 marks)