help ASAP.

hey , kindly can u explain how did the got the andswer of -0.0335 which is KcM/taw1 ? i mean show me the calculation exactly ( with substitution)

i wanted to choose chemical engineeirng ( it was a mistake sorry ... just refuse the Q or transfer it )

An electronic Pl temperature controller has an output p of 12 mA when the set point equals the nominal process temperature. The controller response to step change in the temperature set point of 2.5 mA (equivalent to a change of 5F) is shown below: t, s p. mA 0- 8.0 0+ 6.7 20 6.0 60 4.7 80 4.0 Determine the controller gain K (mA/mA) and the integral time, Ti. Is the controller reverse- acting or direct-acting? The response of a Pl controller to a unit step change in set point at t = 0 is shown in Fig. 8.6. The instantaneous change at t = 0 is Ke and the slope of the response is Kc/TI. Now consider a more general step change in the set point of magnitude M. K. (1+7) M s P(s) 1 = K. (1+ = Ke+ E(3) TIS T13 E(S) KM KM P(s) = KM p(t) = KM + -t for t > 0 TI S 7782 = The instantaneous change at t = 0 is KeM and the slope of the response is KM/T, From the data given in the table, the initial instantaneous change is -1.3 mA and the slope is -0.0335 mA/s for a step change of M = 2.5 m A. Thus, -1.3 mA -1.3 mA Kc = = -0.52 M 2.5 mA KCM = -0.0335 mA/s TI TI = KM -0.0335 mA/s -0.52(2.5 mA) -0.05 mA/S 26 8 Because Kc is negative, we classify this controller as direct acting