Question
Help with homework; PLEASE TYPE ALL ANSWERS AND WORKOUT TYPE ANSWERS Q1. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted
Help with homework; PLEASE TYPE ALL ANSWERS AND WORKOUT TYPE ANSWERS
Q1. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to test whether thepopulation mean percent of CT students who have contracted COVID-19 differs from25%.Let= 0.05.
State the null and alternative hypotheses for this test.
a. H0: = 25
HA: 25
b. H0: p = 25
HA: p 25
c. H0: 25
HA: = 25
d. H0: = 25
HA: < 25
Q2. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to test whether thepopulation mean percent of CT students who have contracted COVID-19 differs from25%.Let= 0.05.
Assume the t-test is the appropriate and the assumptions are met.Perform the test.What is the p-value?
a. 2.3101
b. 0.9891
c. 0.0217
d. 0.0109
Q3. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to test whether thepopulation mean percent of CT students who have contracted COVID-19 differs from25%.Let= 0.05.
Assume the t-test is appropriate, and the assumptions are met.Perform the test.What is the conclusion?
a. The p-value is greater than , so we reject the null hypothesis.
b. The p-value is less than , so we reject the null hypothesis.
c. The p-value is less than , so we fail to reject the null hypothesis.
d. The p-value is greater than , so we fail to reject the null hypothesis.
Q4. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to test whether thepopulation mean percent of CT students who have contracted COVID-19 differs from25%.Let= 0.05.
Assume the t-test is appropriate, and the assumptions are met.Perform the test.What is the interpretation?
a. There is solid evidence against the idea that the population mean percent of CT students who have contracted COVID-19 differs from 25%.
b. There is solid evidence against the idea that the population mean percent of CT students who have contracted COVID-19 equals 25%.
c. There is moderate evidence against the idea that the population mean percent of CT students who have contracted COVID-19 differs from 25%.
d. There is moderate evidence against the idea that the population mean percent of CT students who have contracted COVID-19 equals 25%.
Q5. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to test whether thepopulation mean percent of CT students who have contracted COVID-19 differs from25%.Let= 0.05.
Assume the t-test is appropriate, and the assumptions are met.Perform the test.What would change if= 0.01?
a. The conclusion would not change, but the interpretation would change.
b. Nothing would change.
c. The conclusion would change, and the interpretation would change.
d. The conclusion would change, but the interpretation would remain the same.
Q6. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to study thepopulation mean percent of CT students who have contracted COVID-19.
Assume the t-Interval is appropriate and the assumptions are met.Report the 95% confidence interval.
a. (25.642, 28.858)
b. (25.332, 29.168)
c. (24.722, 29.778)
d. Cannot answer the question with the methods covered in this chapter.
Q7. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to study thepopulation mean percent of CT students who have contracted COVID-19.
Assume the t-Interval is appropriate and the assumptions are met.Interpret the 95% confidence interval in context.
a. We are 95% confident that the population mean is between 28.858% and 25.642%.
b. We are 95% confident that the population proportion of CT students who have contracted COVID-19 is between 24.722% and 29.778%.
c. We are 95% confident that the population mean percent of CT students who have contracted COVID-19 is between 25.332% and 29.168%.
d. We are 99% confident that the population mean percent of CT students who have contracted COVID-19 is between 25.332% and 29.168%.
Q8. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to study thepopulation mean percent of CT students who have contracted COVID-19.
Assume the t-Interval is appropriate and the assumptions are met.What would the confidence interval be if the confidence level was 90%?
a. (25.642, 28.858)
b. (25.332, 29.168)
c. (24.722, 29.778)
d. We cannot answer using the methods in this chapter.
Q9. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to study thepopulation mean percent of CT students who have contracted COVID-19.
Assume the t-Interval is appropriate and the assumptions are met.What would the confidence interval be if the confidence level was 99%?
a. (25.642, 28.858)
b. (25.332, 29.168)
c.(24.722, 29.778)
d. We cannot answer using the methods in this chapter.
Q10. Ahealthcarecompanyis studying 250 Connecticut schools, and measures the percent ofstudents who have contracted COVID-19.The variable is Normally distributed, with mean27.25% and standard deviation 15.4%.The healthcare company wants to study thepopulation mean percent of CT students who have contracted COVID-19.
Assume the t-Interval is appropriate and the assumptions are met.Using the 95% confidence interval, is there evidence that the population mean
percent of CT students who have contracted COVID-19 is 29%?Why or why not?
a. There is evidence, because 29% is inside the confidence interval.
b. There is no evidence, because 29% is inside the confidence interval.
c.There is no evidence, because 29% is outside the confidence interval.
d. There is evidence, because 29% is outside the confidence interval.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started