Here is my code please create the test plan with comments and answer the reflection questions
if j *********** 5 def count_type (map_data, map_type): 6 count = 0 7 for i in map_data: 8 for j in i: 9 == map_type: 10 count += 1 11 return count 12 #For this function I am using nested loops and inside the inner loop I am checking if the element is equal to map 13 14 #******** ********* 15 # Write your classify_map function below: (4 marks) 16 #******************************************** 17 18 def classify_map (map_data): 19 for i in map_data: 20 if count_type(i, "R") > (len(map_data)*len(i))/2: 21 return "Suburban" 22 elif count_type(i, "A") > (len(map_data)*len(i))/2: 23 return "Farmland" 24 elif (count_type(i, "U") + count_type(i, "U")) > (len(map_data) *len(i))/2: 25 return "Conversation" 26 elif (count_type(i, "C") > (len(map_data) *len(i)/2)) and (count_type(i, "U") + count_type(i, "A")) >= 0.1 27 return "City" 28 else: 29 return "Mixed" 20 6 7 def isolate_type (map_data, map_type): 8 new_list = map_data.copy ( ) 9 idx_i = 0 0 for i in new list: 1 idx_j = 0 2 for j in i: 3 if j != map_type: 4 new_list[idx_i][idx_j] 5 idx_j += 1 6 idx_i += 11 7 return new_list 8 9 #1 firstly create a copy of the original list, then I loop through the copied list and check if the element 0 1 #*************** *********************** 2 # Write your commercially_buildable function below: (2 marks) 3 #******************************************** 4 def commercially_buildable(map_data,i,j): 5 # some condition check 6 if(map_data[i][j]): 7 return True 8 else: 9 return false 0 1 MAP = I'A' '' ' 'A' '' 'I' '' "IT' 1 Test Plan Develop a test plan for your program. Your test plan should have at least three test cases: one normal case, one boundary case, and one abnormal case. You can test any function but you must test at least two different functions. Please use the following format for your test cases: Function: Input: Output: Expected Output: Pass/Fail: An example test case is shown below: 'T' , 'A'), Function: count_type (map_data, map_type) Input: map_data = [['U', 'U','A'], ['R','T', 'W', ['U','T','A', 'W']] map_type = 'U' Output: 3 Expected Output: 3 Pass/Fail: Pass Implement your testing plan in the cell below! 1. Which functions did you use a nested structure (nested loops, nested conditionals, etc) to implement the requirements? Would it have been possible to implement them without using a nested structure? Which functions did you not use a nested structure? Would it have been possible to implement them with a nested structure? 2. Suppose we wanted to create an additional map classification called 'Urban City' which is indicated by the number of 'R' cells plus the number of 'C' cells being between 60% and 80%. Can we do this? How might this affect our classify_map() function? 3. How many test cases would you need to confirm that your classify_map() function correctly identifies a "Farmland" map? Explain what your test cases would be
