hey the answer is 7.2 106 m3 /s but pls show steps on how to get there

The device shown (not to scale) uses an area change and a manometer to measure the volume flow rate through a pipe. Liquid 1(1=1600kg/m3) flows steadily through a contraction from diameter DA=5mm to DB=3mm. Liquid 2(2=3400kg/m3) and Liquid 3(3=600kg/m3) remain motionless in the manometer tube. The heights indicated in the diagram are a=3cm, b=2cm,c=1cm,d=1cm, and h=3cm. Assume the manometer tubes are wide enough to neglect surface tension effects but narrow enough to neglect height variation across the diameter. Neglecting losses, calculate the volume flow rate through t