Hi expert please answer all the questions from this part will do like immediately. Thank you

Part II: Guided Problems 1. For a certain population, the chance someone will have a pet dog is 64%. The chance someone will have a pet cat is 42%. The chance someone will have both a pet dog and a pet cat is 28%. Use the conditional probability formula (division rule) to answer the following questions. (a) If someone has a pet dog, what are the chances he has a pet cat? (b) If someone has a pet cat, what are the chances he has a pet dog? (c) True or false: having a dog and having a cat are independent events for this population. 2. A standard deck of 52 cards is well-shuffled. Two cards are drawn in order without replacement. Use the law of total probability to find the chances the second card will be a king, regardless of what the first card was. 3. Two urns are filled with marbles. The first um has 2 red and 8 blue marbles. The second urn has 18 red and 6 blue marbles. An urn is randomly selected and a marble is drawn. (a) Find the total probability of drawing a red marble. (b) Use Bayes' rule to find the chance that you drew from the second urn, if you draw a red marble. (c) + This experiment involves 34 marbles and 20 of them are red. Why isn't the total probability of drawing a red marble simply 20/34? 4. Refrigerators are distributed from four factories, as follows: Factory A Factory B Factory C Factory D 40% 26% 20% 14% The chance of a damaged refrigerator being shipped from each factory is: Factory A Factory B Factory C Factory D 5% 3% 2% 1% Continues on the next page . (a) Use the law of total probability to find the chance that a damaged refrigerator is shipped. (b) If a refrigerator arrives damaged, find the chance it came from Factory A. (c) Find the chance the damaged refrigerator came from each of the other factories. Are these chances related in any way? 5. Six identical urns are filled with marbles. The first urn has 99 blue marbles and 1 red marble. The second and third urns each have 6 blue marbles and 4 red marbles. The fourth, fifth, and sixth urns each have 1 blue marble and 1 red marble in each. (a) If we select an urn randomly and draw a marble, what is the probability it will be red (regardless of which um we picked)? (b) It so happens that we draw a red marble. Use Bayes' rule to find the chance that we drew from each type of urn. (c) If we dump all the marbles into one urn and draw a marble, what is the probability it will be red? Should this be the same as the probability in part (a)