Hi,

I would like to understand the step D in this question.

alto ol o % 0 U 0 A university would like to develop a regression model to predict the point differential for games played by its men's basketball team. A point differential is the difference between the final points scored by two competing teams_ A positive differential is a win for the university's team and a negative differential is a loss For a random sample of games, the point differential (y) was calculated, along with the number of assists (x4), rebounds (x, ), turnovers (x,), and personal fouls (x,). Complete parts a through f below. @ Click the icon to view the data for the random sample of games. a) Construct a regression model using all four independent variables. v=(-4552) (07260 ) x, = (13772 x, + (01295 ) xg + ( -01415)x, (Round the constant to two decimal places as needed. Round the x4, X3, X3, and x4 coefficients to four decimal places as needed ) b) Interpret the meaning of the regression coefficients. Select the correct choice below and, if necessary, fill in the answer boxes within your choice. (Round to four decimal places as needed ) Y Each assist increases the point differential by 0.7260 = Each rebound increases the paint differential by 1.377 = Each turnover increases the point differential by 0.1295 = Each personal foul decreases the point differential by 0.1415 Each assist decreases the peint differential by Each rebound decreases the point differential by . Each turnover decreases the point differential by Each personal foul increases the point differential by There is no meaningful interpretation of the regression coefficients for this application c) Predict the average point differential for a game in which the university's team had 12 assists, 21 rebounds, 19 turnovers, and 20 personal fouls g: -8.26 (Round to two decimal places as needed.) d) Construct a 95% confidence interval for the game described in part c. Interpret the meaning of the interval The 95% confidence interval is from a lower limit of - 2155 to an upper limit of 504" (Round to two decimal places as needed.)