Hi, this is 1 question with multiple parts. The answers are already given. However, I truly want to understand how to go about such problems. If its not too much to ask, I would appreciate anyone who can write down the steps to solving these problems. I thank you in advance

Fill in the right-hand column of the following table to describe the processing of the irmovq instruction on line 4 of the object code in (Figure 1): Stage Fetch Generic irmova V, TB icode: ifun M1[PC] rA: B M 1[PC + 1] valC+ M 8[PC + 2] valp PC + 10 Specific irmovq $128, %rsp A B D valE+ 0 + valc E Decode Execute Memory Write back PC update F R[rB] + valE PC + valp G 1 2 3 4 5 6 0x000: 30820900000000000000 irmovq $9, %rdx 0x00a: 30f31500000000000000 irmovq $21, %rbx Ox014: 6123 subq %rdx, %rbx 0x016: 30148000000000000000 irmovq $128, %rsp 0x020: 40436400000000000000 rmmovq %rsp, 100(%rbx) Ox02a: a02f 1 pushq %rdx 7 0x02c: boof 8 OxO2e: 734000000000000000 je done Ox037: 804100000000000000 call proc 10 Ox040: | done: Ox040: 00 1 halt 12 Ox041: I proc: Ox041: 90 1 # subtract # Problem 4.13 # store # push # Problem 4.14 # Not taken # Problem 4.18 popq Xrax 9 ret 13 14 # Return What should be in position A? icode: ifun + M1[128]= 3:0 icode: ifun + M1[0x016]= 3:0 icode: ifun + M1[0x00F]= 3:0 O icode : ifun + M1[0x128]= 4:0 What should be in position B? rA:rB+ M1[17]=f:4 OrAirB+ M1[21]=f:4 rAirB+ M1[0x021]=f.4 rAirB M1[0x017]=f.4 What should be in position C? valc + M8[0x018]= 120 valc M8[0x01A]= 122 valC+ M8[0x018]= 128 valC+ M1Ox019]= 128 What should be in position D? valP+ 0x018 + 7 = 0x020 valp 0x016 + 11 = 0x020 valP+ 0x015 + 9 = 0x01F valP - Ox016 + 10 = Ox020 What should be in position E? valE+ 0 + 128 = 128 valE+ 2 + 128 = 130 valE+ 0 + 122 = 122 valE+ 1 + 120 = 122 What should be in position F? R[%rsp] + valE = 122 R[%rdx] + valE = 122 R[%rsp] + valE = 128 R[%rsp] + valE = 130