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How can such integration be solved by hand? This is common in thermodynamics textbooks. Please show work how this integration is done IDCPH(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=23.121IDCPS(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=0.0692
How can such integration be solved by hand? This is common in thermodynamics textbooks. Please show work how this integration is done
IDCPH(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=23.121IDCPS(298.15,418.15;1.376,4.157E3,1.610E6,0.121E+5)=0.0692Step by Step Solution
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