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how did he get the values of 0.8044, 0.7871, 0.7702, and 0.1797? End-of-month deposit = [4,000(P/F, 2.2%, 10) + 4,000(P/F, 2.2%, 11) + 4,000(P/F, 2.2%,
how did he get the values of 0.8044, 0.7871, 0.7702, and 0.1797?
End-of-month deposit = [4,000(P/F, 2.2%, 10) + 4,000(P/F, 2.2%, 11) + 4,000(P/F, 2.2%, 12)] (A/P, 2.2%, 6) = = = [4,000(0.8044) + 4,000(0.7871) + 4,000(0.7702)] (0.1797) = (3,217.6 +3,148.4 + 3,080.8) (0.1797) = 9,446.8(0.1797) = $1,698 Thus, the required end-of-month deposit for six month is $1.698Step by Step Solution
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