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2. The figure on the right shows the states fed in the decay of 0+ 0.0 162.86 D band in 242 Cr 24 Cm146 Q(gs)-6215.56 kev 8 a. What type of decay is this (1 pts.)? a : 100 % HF 10 0+ 1184. 1228.7 88 979. - 1125. 1081. 686 ...545:5::":": 45:" 1018.6 b. What is the energy of the particle emitted in the 974.5 11.9 0+ -941.4 336.4 decay of 296Cm when the state at the top of the 897.3: level scheme is populated. (2 pts.) 24432 3- - 763.2 459. 8 i 1712 3- 617.2 -661.3 183 1- 515.3 561 617.2 605.1 . . 7544 8+ 605 -513.6 210.2 458 6+ - 303.4 157.4 395 4+ 101.9 - 146 1.733 2+ 0+ - 44.1. 177 PS 44.19 0.0. 87.74 Y 250PU14 c. What type of structure does the product nucleus (294Pu) have? How did you determine that (2 pts.)? d. Use the 29: Pu level scheme to predict the energy of the y-ray de-exciting the yrast 10* level. You may neglect recoil. (2 pts.). e. The internal conversion coefficient of the gamma-ray emitted in the decay of the yrast 2* level is 785. What would you estimate for its lifetime in a fully-ionized 238 Pu atom (1 pts.)? f. (Extra Credit) Use the information from part e) above to determine the lifetime of the yrast J"=8* level if the internal conversion coefficient for the y-ray de- exciting the 8* level is 0. (1 pt.)CONSTANTS CO. Speed of light 2.99792458 x 108 m/s Charge of electron 1.602189 x 10-19 C Boltzmann constant 1.38066 X 10-23 J/K 8.6174 X 10 -5 eV/K Planck's constant h 6.62618 X 10-34 J . S 4.13570 x 10 -15 e eVS . h= h/2n 1.054589.X 10 34.J 34 . J. 6.58217 x 10-16 eV . s Gravitational constant G 6.6726 X 10-11 N . m2 /kg2 Avogadro's number NA 6.022045 x 1023 mole -1 Universal gas constant K 8.3144 J/mole . K Stefan-Boltzmann constant 5.6703 X 10-8 W/m2 . K4 Rydberg constant 1.0973732 x 10' m-1 Hydrogen ionization energy 13.60580 eV Bohr radius do 5.291771 x 10-11 m Bohr magneton P B 9.27408 X 10-24 J/T 5.78838 X 10-eV/T Nuclear magneton 5.05084 X 10-27 J/T 3.15245 x 10-8 eV/T Fine structure constant 1/137.0360 hc 1239.853 MeV . fm hc 197.329 MeV . fm e 2/4 TIED 1.439976 MeV . fm PARTICLE REST MASSES MeV/c2 Electron 5.485803 X 10-4 0.511003 Proton 1.00727647 938.280 Neutron 1.00866501 939.573 Deuteron 2.01355321 1875.628 Alpha 4.00150618 3727.409 0.1498300 139.5669 0.1448999 134.9745 0.1134292 105.6595 CONVERSION FACTORS 1 e.V = 1.602189 X 10-19 J 1 b = 10-28 m2 1 u = 931.502 MeV/c2 1 Ci = 3.7 x 1010 decays/s = 1.660566 X 10-27 kgShow your work and explain your reasoning clearly. You are allowed one page of notes (both sides). PLEASE WRITE YOUR STUDENT ID ON ALL PAGES! PLEASE PUT THE PROBLEM # ON TOP OF ANY ADDITIONAL SHEETS YOU USE! Group - 1 2 7 9 10 11 12 13 15 16 17 18 Period 2 I He 4 10 Be N O Ne 11 12 14 15 16 18 Na Ma Al 5 Ar 19 20 21 23 24 25 26 27 28 29 30 31 32 33 34 35 36 ca Sc V Cr Mn Fe Co Ni Cu Zn Ga Ge AS Se Kr 38 39 40 43 45 46 48 49 50 TC 52 53 54 Rb Sr Zr Nb Mo To Ru 3h Pd Ag Cd In Sn sb Te Xe 56 12 76 78 79 80 81 32 84 86 CS Ba Hf Ta W Re Os pt Au Ha TI Ri Po At Rn 87 88 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 Ra Rf Db Sq HS Mt DS Rg En Mh Mc LV TS Og Lanthanides 57 58 59 60 62 63 64 65 66 67 68 69 70 71 La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Actinides 89 90 91 93 94 95 96 9 98 99 100 101 102 103 Ac Th Pa Np Pu Am Cm BK Cf ES Fm Md No Lr (E1) = 1.0 x 1014 A2/3 E3 MIC 1(E2) = 7.3 x 107 A4/3E5 Atotal = Ay (1 + a); a = (E3) = 34 A2 EZ Feather's Rule: (E4) = 1.1 x 10-5 A8/3 E9 Energy (MeV) Range (cmz) = 2 1(E5) = 2.4 x 10-12 A10/3 E11 A(M1) = 5.6 X 1013 E3 Bragg-Kleeman Rule: 2(M2) = 3.5 x 107 A2/3 E5 R1 _ P2 VA1 2(M3) = 16 A4/3 EZ R2 P1 VA 2 2(M4) = 4.5 x 10-6 ARE9 2(M5) = 7.4 x 10-13 A8/3611 At = 8 sing