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How many grams of Br, are needed to form 72.6 g of AlBrz? 2 Al(s) + 3 Br2(1) 2 AlBrz(s) Step 1: Show the strategy
How many grams of Br, are needed to form 72.6 g of AlBrz? 2 Al(s) + 3 Br2(1) 2 AlBrz(s) Step 1: Show the strategy for solving this problem. grams AIBr; grams Br2 Answer Bank grams AIB, grams A1 moles AI grams Br moles Br moles AlBrz Step 2: Show the conversions required to solve this problem and calculate the grams of Brz. 72.6 g AlBrz X = g Br Answer Bank 26.98 g AI 1 mole A1 2 moles A1 159.80 g Br2 1 mole Br 3 moles Br, 266.68 g AlBrz 1 mole AlBr 2 moles AlBr grams of Bry: g Brz
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