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How many mL of 0.23M HCl is needed to completely react with 3.25 g of Al(OH)(MM = 78.0 g/mol) 3HCl(aq) + Al(OH) (s) AICI(aq) +
How many mL of 0.23M HCl is needed to completely react with 3.25 g of Al(OH)(MM = 78.0 g/mol) 3HCl(aq) + Al(OH) (s) AICI(aq) + 3HO(l) a. 278 mL b. 0.543 mL c. 725 mL d. 543 mL e. 122 mL
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Biochemistry Concepts and Connections
Authors: Dean R. Appling, Spencer J. Anthony Cahill, Christopher K. Mathews
1st edition
