HW: Calculation of Lab Students Blood Group Genotypes and Alleles Frequencies _-\" Fre uenc 0 Students A Students B Students AB Students q y 500! Total 1000= 300/ Total 1000 = 150/ Total 1000 = 50 I Total 1000 = - Then 0 genotype frequency_r2_= - so r (0 allele frequency) = \\f r2 = , , r = - Alleles frequencies of A + 0 ( temporarily \"ignoring\" B ): = (92 + Zpr + r2) = (p + r)2 (It's a Mathematic Law). - + = (p + r)2 Then \\I = p + r - So, p = r , p (A allele frequency) = = , p = Thus, p2 = ( )2 = - Alleles frequencies of B + 0 (temporarily \"ignoring\" A): = (92 + 2gr + r2) = (q + r)2 (It's a Mathematic Law). + = (q + r)2 Then \\l = q + r - So, q = r , q (B allele frequency) = - = , q = Thus, q2 = ( )2 = To check, the sum of all alleles frequencies: p + q + r = 1 - Thus: + + = 1, so it is correct ? - Also, all Genotypes frequencies = p2 + 2pr + q2 + 2qr + 2pq + r2 = 1 ( )2+2( )( )+( )2+2( )( )+2( )( )+( )2= - so it is correct? at 1.0 so it is correct. 0 (A= %).+(B= %.)+(AB= %)+(0= %) = %