I am matching your answer with mine , so just the final result will be okay , no explanation needed

Thank you !!

Section 2.3: Problem 21 (1 point) Previous Problem Problem List Next Problem Find the first and second derivatives of the function. f(x) = 4sin x + 6 cos I. f'(x) = f"(x) =Section 2.3: Problem 22 (1 point) Previous Problem Problem List Next Problem Find the points on the graph of f(x) = 2x* + 9x - 108x + 11 where the tangent is horizontal. List the c-values of these points. I value(S)= (Separate answers by commas if there are more than one.)Section 2.3: Problem 23 (1 point) Previous Problem Problem List Next Problem For what value(s) of * is the tangent line to the graph of f(x) = 10x3-60x2 + 120 parallel to the line y = -2? If there is more than one value of c, list them as a comma separated list.Section 2.3: Problem 24 (1 point) Previous Problem Problem List Next Problem At what point does the line normal to the graph of y = 2 - 3x + 4x at (1, 3) intersect the parabola a second time? Hint: The normal line is perpendicular to the tangent line. If two lines are perpendicular their slopes are negative reciprocals -- i.e. if the slope of the first line is m then the slope of the second line is -1/mSection 2.3: Problem 25 (1 point) Previous Problem Problem List Next Problem The position of a particle moving on a horizontal line (where s is in meters to the right of a fixed reference point and t in seconds after the start of the observation) is s = (1/3)+3 - 7+2 + 49t + 5. (a) Find the velocity and acceleration as functions of t. Velocity, in meters per second, at time t : Acceleration, in meters per second, per second, at time t : (b) Find the acceleration after 1 second. Acceleration, in meters per second, per second, after 1 second : (c) Find the acceleration at the instant when the velocity is 0. Acceleration, in meters per second, per second :Section 2.3: Problem 26 (1 point) Previous Problem Problem List Next Problem The position of a particle moving on a horizontal line (where s is in feet to the right of a fixed reference point and t is in seconds after the start of the observation) is s(t) = t* - 12t + 24, t> 0. (A) Find the velocity, in feet per second, at time t: v(t) = (B) Find the velocity (in ft/sec) of the particle at time t = 3 (C) Find all values of t for which the particle is at rest. (If there are no such values, enter none . If there are more than one value, list them separated by commas.) t = (D) Use interval notation to indicate when the particle is moving in the positive direction. (If needed, enter inf for co. If the particle is never moving in the positive direction, enter none .) (E) Find the total distance (in feet) traveled during the first 8 seconds.Section 2.3: Problem 27 (1 point) Previous Problem Problem List Next Problem If a ball is thrown vertically upward from the roof of a 32-foot high building with a velocity of 80 ft/sec, its height, in feet, after t seconds is s(t) = 32 + 80t - 16t-. a.) What is the maximum height, in feet, the ball reaches? Answer: b.) What is the velocity, in feet per second, of the ball when it hits the ground (height 0)? Answer:Section 2.3: Problem 28 (1 point) Previous Problem Problem List Next Problem A spherical balloon is being inflated. Find the rate of increase (with respect to its radius, in inches, r) of the surface area, in square inches, (S = 4xr?) when: (A) r = 1 inches -> Rate of increase, in square inches per second, = (B) r = 4 inches -> Rate of increase, in square inches per second, = (C) r = 6 inches -> Rate of increase, in square inches per second, =Section 2.1: Problem 1 (1 point) Previous Problem Problem List Next Problem ATTEMPT NOT ACCEPTED -- Please submit answers again (or request new version if necessary). Let h(x) = 5 -2x3, h' ( 2) = -24 Use this to find the equation of the tangent line to the curve y = 5 - 2x* at the point (2, -11) and write your answer in the form: y = mx + b, where m is the slope and b is the y-intercept