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I can't solve the following game theory, can you help me? Player 2 A B C 1/3, 2/3 0, 0 player 1 D 0, 0

I can't solve the following game theory, can you help me?

Player 2

A B

C 1/3, 2/3 0, 0

player 1

D 0, 0 1, 1

If the Player 1 plays a mixed strategy and choose C, why the probability is 3/5 and not 3/4?

Furthermore, assume that 1/3 and 2/3 are y and (1-y). If y is a number between 0 and 1, the game has three Nash Equilibria, why? I have found only 2.

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