I have already solved the first parts of this question, I am just stuck on how to solve part e, I don't know how to get the mole fractions with the information that we are given here.

6. (2D27) For the Antoine equation in the form Image with VP in mm Hg and T in C, B log10(VP)=A- T+C the constants for n-pentane are A = 6.853, B = 1064.8, C = 233.01. n-hexane constants are A 6.876, B = 1171.17, C = 224.41 (Speight, 2005). (a) Predict the vapor pressure at 0C for pure n-pentane. (b) Predict the boiling point of pure n-pentane at 3.0 atm pressure. (c) Predict the boiling pressure if pure n-pentane is boiling at 0C. (d) At a pressure of 500.0 mm Hg and temperature of 30C, predict the K values for n-pentane and n-hexane using Raoult's law. = (e) If T = 30C and p = 500.0 mm Hg, determine the mole fractions in the liquid and vapor phases of an equilibrium mixture of n-pentane and n-hexane. (f) One mole of a mixture that is 75.0 mol% n-pentane and 25.0 mol% n-hexane is placed in a closed chamber. The pressure is adjusted to 500.0 mm Hg, and the temperature to 30C. The vapor and liquid mole fraction were found in part e. How many moles of liquid and moles of vapor are there at equilibrium? (g) If 1.0 mol/min of a mixture that is 75.0 mol% n-pentane and 25.0 mol% n-hexane is fed