I just can't seem to get the my X = 0.05 when Length = 1. Using step size L of 1.

My k1, k2, k3, k4 are:

k1, k2, k3, k4 = 1*(0.65267*56791.1128*706/2*555.87) = 9.661*10^4

T1 = 0 + 1/6*(9.661*10^4 + 2(9.661*10^4) + 2(9.661*10^4) + (9.661*10^4)) = 9.661*10^4

this clearly isn't 0.05 so pls help. If the differential equation I use to find my k1, k2, k3, k4 is wrong, can show how to derive the correct one and redo everything again. Also, can show how does dX/dL = n x R_NH3 x A / 2 x F_N2 becomes dX/dL = n x R_NH3 x A x (2 x F_N2 / 2 x F_N2 x (1-X)) cause I am confused how does the X and another 2 x F_N2 come out on the right-hand side when there isn't any X on the right-hand side of the original equation given at all as this seems to be the differential equation to be used in the 4th order Runge-Kutta method???

Catalyst effectiveness factor ()=0.652670905 Reaction rate of ammonia (RNH3)=56791.1128kmol/m3.hr Area of reactor (A)=706m2 Molar flowrate of Nitrogen (FN2)=135.43kmol/hr X(0)=0L(0)=0 Question: Solve dLdX=2FN2RNHSA using 4th order Runge Kutta method and plot a Conversion (X) vs Length (L) graph using Excel. Please show a detailed working of which values were used how to get the k1,k2k3 and k4 values using Length = 1 as the example. Also provide Excel sheet if possible. Note: Please show how to derive the differential equation used for the 4th order Runge Kutta method and what each cell A, B, C, etc. in Excel means too