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CHALLENGE ACTIVITY 1.5.3: Expand then reduce the proposition. Jump to level 1 1 Simplify -(-2+(-ma-q)) to -qam 2 Laws Distributive (a b) v(anc) = Complement av a = T an(bvc) (avb) (avc) = av(bac) EF 1. Select a next law from the right to apply -(-9+(-ma-q)) -(-9+(-01-m)) -(-9v(-91-m)) -(qv(-qa-m)) -((qv-q)^(qv-m)) -T EF Commutative avb bva -F b b Identity UNDO LAW Ea De Morgan's -() -av-b avF = a (avb) E -an-b Double negation E a Conditional a ab avb ab (a+b)( ba) 2 Check Next Feedback