If $100\mathrm{.}0$ mL of $0\mathrm{.}100$ M of acetic acid, HCH$3$COO, is added to $100\mathrm{.}0$ mL of $0\mathrm{.}100$ M potassium hydroxide, KOH, calculate the pH of the resulting solution. The Ka of acetic acid is $1\mathrm{.}8$x$10^-5.$