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If 1.50 moles of nitrogen gas reacts with an excess of hydrogen gas, what mass of ammonia (NH) would be produced? [N + 3H -->
If 1.50 moles of nitrogen gas reacts with an excess of hydrogen gas, what mass of ammonia (NH) would be produced? [N + 3H --> 2NH; N = 14.0 g/mol, H = 1.01 g/mol]
a.)51.1 g
- a.)Correct.First, write the balanced chemical equation. Then, use the stoichiometric ratio from the balanced equation to convert moles of N to moles of NH, then convert moles of NH to g NH using molar mass.
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