If you would not fully evaporate the acetone in the IR sample preparation, what issue would it cause?

The C$-$H stretches from acetone would obscure this region and we would not be able to tell if the product formed.

Acetone would dissolve and damage the expensive salt plates.

The carbonyl peak from the acetone may be confused with camphor.

The carbonyl from acetone would react with the alcohol product and turn it into a carboxylic acid.

Acetone and the sample would continue to evaporate during the scan and we would get a blank spectrum.