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I'm a little bit stuck with the part of the following example: The stationary points of y are when this is zero, so when 3a2
I'm a little bit stuck with the part of the following example:
The stationary points of y are when this is zero, so when 3a2 - 40a + 100 = 0 3a2 - 10a - 30a + 100 = 0 a(3a - 10) - 10(3a - 10) = 0 (a - 10)(3a - 10) = 0 so either a - 10 = 0 a = 10 or 30 - 10 = 0 3a = 10 10 3Step by Step Solution
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