Question
In a railway marshaling yard, goods trains arrive at a rate of 30 trains per day . Assume that inter-arrival time and the service time
In a railway marshaling yard, goods trains arrive at a rate of 30 trains per day.
Assume that inter-arrival time and the service time distribution follow an exponential distribution with an average of 36 minutes.
Using M/M/I Calculate and Explain the following:
- Service Rate
- Mean queue size
- Service Utilization
- Expected No of units Waiting in the system
- Expected Waiting Time in the system
- Expected Waiting Time in the Queue
- The probability that queue size exceeds 11
- If the input of the train increases to an average of 35 per day, what will be the changes in queue size?
M/M/I probability formula: P n = (lambda / mean)^2 * (1 - lambda / mean)
Please Explain the steps in details.
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Answer a Arrival rate 30 trains per day Service rate 246036 40 trains per day Mean queue size Lq 2 3...Get Instant Access to Expert-Tailored Solutions
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