In a study of cell phone usage and brain hemispheric dominance. an Internet survey was e-mailed to 6993 subjects randomly selected from an online group involved with ears. There were 1311 surveys returned. Use a 0.01 signicance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. E) Identify the null hypothesis and alternative hypothesis. 0 A. H0: p0.2 O B. H0: p=0.2 H1:p=0.2 H1:p#0.2 O C. H0: p0.2 H1:p=0.2 H1:p=0.2 O E. H0: p=0.2 O F. H0: p=0.2 H1:p0.2 The test statistic is z = D. (Round to two decimal places as needed.) The Pvalue is D. (Round to three decimal places as needed.) Because the Pvalue is |:| the signicance level, |:| the null hypothesis. There is El evidence to support the claim that the return rate is less than 20%. Because the P-value is the significance level, the null hypothesis. T is less than 20%. greater than less thanBecause the P-value is the significance level, the null hypothe is less than 20%. reject fail to rejectThere is evidence insufficient sufficient