In dilute sulfuric acid, an iron tablet weighing $0\mathrm{.}960$ g was dissolved. To reach the endpoint, an average titre of $28\mathrm{.}50$ ml of $0\mathrm{.}0180$ mol$/$L potassium manganate$($VII$)$ solution was required. What is the iron percentage of the tablet in terms of mass? The equation of the reaction is: MnO$4($aq$)+8$H $2+2+3+($aq$)+5$Fe Mn $($aq$)+5$Fe $($aq$)+4$H$2$O $($l$)$

a$.80\%$

b$.15\%$

c$.30\%$

d$.60\%$