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in general, how do you think the equivalent mass of the pulley will relate to its actual mass? Activity C (continued from previous page) 5.
in general, how do you think the equivalent mass of the pulley will relate to its actual mass?
Activity C (continued from previous page) 5. Make a rule: In general, how do you think the equivalent mass of the pulley will relate to its actual mass? 6. Test: Set Mass A to 1.0 kg, Mass B to 3.0 kg, and the Pulley Mass to 4.0 kg. A. What is the total force on masses A and B? 19.62 N B. Click Play, and select the TABLE tab. What is the final velocity? 2.35 m/s C. What is the time? 0. 785 D. What is the acceleration? 3.27 m ($2 E. Based on the force and acceleration and Newton's second law (F = ma), what is the equivalent mass of the system? G ug m : - 6 KB F. Subtract the masses of objects A and B from this value to find the equivalent mass of the pulley: 2 kg - - ( 1 kg + 3 kg ) = 6 kg - 4 kg ( 2ng G. Did this experiment confirm the rule you made in question 5? Explain. Yes, this is because when you subtract the sum of all the misses from the whole system, you get the moss of the pelley. 7. Apply: What will be the acceleration of an Atwood machine with a frictional pulley with the following mass values? When you are done, use the Gizmo to check your answer. Pulley: 3.6 kg Mass A: 1.4 kg Mass B: 4.1 kg Acceleration: 3.62 m/s2 Show your work: Mass H: V $2.68 refering to bot moss A PB 7.4 x 9.81: 13 73M t = 0.74 5 3.62 m/s2 = 3.62 m/s2 3 messured occelection Moss B: not to be ased right 4. 1 x 9.81 = 40.22 N now Totbl Force : F 26.49 3 = 10.22 - 13.73 m = 26.49 N GizmosStep by Step Solution
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