In need of assistance with the following questions. Hand written or typed is fine, explanations appreciated. There are approximately 14 questions. Thanks in advance. 3. The graph of a normal curve is 6101418222630X given on the right. Use the graph to identify the values of A normal curve has a horizontal axis labeled "X" from 6 to 30 in intervals of 4, where the curve's peak is near the top of the graph at horizontal coordinate 18. Five vertical line segments running from the horizontal axis to the curve are at horizontal coordinates 10, 14, 18, 22, and 26. mu and sigma. muequals= nothing sigmaequals= nothing QUESTION 4. Determine the area under the standard normal curve that lies to the left of (a) Upper Z equals 0.58 commaZ=0.58, (b) Upper Z equals 1.54Z=1.54, (c) Upper Z equals negative 0.39Z=0.39, and (d) Upper Z equals 0.96Z=0.96. 1 Click the icon to view a table of areas under the normal curve. (a) The area to the left of Zequals=0.580.58 is nothing . (Round to four decimal places as needed.) (b) The area to the left of Zequals=1.541.54 is nothing . (Round to four decimal places as needed.) (c) The area to the left of Zequals=negative 0.390.39 is nothing . (Round to four decimal places as needed.) (d) The area to the left of Zequals=0.960.96 is nothing . (Round to four decimal places as needed.) 1: Tables of Areas under the Normal Curve QUESTION 5. Determine the area under the standard normal curve that lies between left parenthesis a right parenthesis Upper Z equals negative 1.24(a) Z=1.24 and Upper Z equals 1.24Z=1.24, (b) Upper Z equals negative 0.81Z=0.81 and Upper Z equals 0Z=0, and (c) Upper Z equals 0.69Z=0.69 and Upper Z equals 2.27Z=2.27. 2 Click the icon to view a table of areas under the normal curve. (a) The area that lies between Upper Z equals negative 1.24Z=1.24 and Upper Z equals 1.24Z=1.24 is nothing . (Round to four decimal places as needed.) (b) The area that lies between Upper Z equals negative 0.81Z=0.81 and Upper Z equals 0Z=0 is nothing . (Round to four decimal places as needed.) (c) The area that lies between Upper Z equals 0.69Z=0.69 and Upper Z equals 2.27Z=2.27 is nothing . (Round to four decimal places as needed.) 2: Tables of Areas under the Normal Curve QUESTION 6. Determine the total area under the standard normal curve in parts (a) through (c) below. 3 Click the icon to view a table of areas under the normal curve. (a) Find the area under the normal curve to the left of zequals=negative 11 plus the area under the normal curve to the right of zequals=11. The combined area is 0.3174 0.3174. (Round to four decimal places as needed.) (b) Find the area under the normal curve to the left of zequals=negative 1.521.52 plus the area under the normal curve to the right of zequals=2.522.52. The combined area is 0.0701 0.0701. (Round to four decimal places as needed.) (c) Find the area under the normal curve to the left of zequals=negative 0.210.21 plus the area under the normal curve to the right of zequals=1.301.30. The combined area is nothing . (Round to four decimal places as needed.) 3: Tables of Areas under the Normal Curve YOU ANSWERED: . 1587.1587 QUESTION 7. Assume the random variable X is normally distributed with mean mu equals 50=50 and standard deviation sigma equals 7=7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. Upper P left parenthesis Upper X greater than 41 right parenthesisP(X>41) 4 Click the icon to view a table of areas under the normal curve. Which of the following normal curves corresponds to Upper P left parenthesis Upper X greater than 41 right parenthesisP(X>41)? A. Answer is not correct 4141 5050 A normal curve has a horizontal axis with two labeled coordinates, 41 and 50. The curve's peak is near the top of the graph at horizontal coordinate 50. Two vertical line segments run from the horizontal axis to the curve at horizontal coordinates 41 and 50. The area under the curve to the left of the left vertical line segment is shaded. Your answer is not correct. B. 4141 5050 A normal curve has a horizontal axis with two labeled coordinates, 41 and 50. The curve's peak is near the top of the graph at horizontal coordinate 50. Two vertical line segments run from the horizontal axis to the curve at horizontal coordinates 41 and 50. The area under the curve between the vertical line segments is shaded. C. 4141 5050 A normal curve has a horizontal axis with two labeled coordinates, 41 and 50. The curve's peak is near the top of the graph at horizontal coordinate 50. Two vertical line segments run from the horizontal axis to the curve at horizontal coordinates 41 and 50. The area under the curve to the right of the left vertical line segment is shaded. This is the correct answer. Upper P left parenthesis Upper X greater than 41 right parenthesisP(X>41)equals= 0.9007 0.9007 (Round to four decimal places as needed.) 4: Tables of Areas under the Normal Curve A table of areas under the standard normal distribution. A symmetric bell-shaped curve is plotted over a horizontal axis. A vert ical line runs from the axis to the curve at a location to the left of the curve's center, labeled z. The area under the curv e to the left of z is shaded and labeled "Area." The values in the table are provided in the copyable data table. YOU ANSWERED: A. . 0985.0985 QUESTION 8. Assume the random variable X is normally distributed with mean mu equals 50=50 and standard deviation sigma equals 7=7. Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. Upper P left parenthesis 34 less than Upper X less than 61 right parenthesisP(34p. Assume the size of the population is 25 comma 00025,000. nequals=800800, pequals=0.60.6 Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caret<="" path="">p below. A. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. B. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. C. Not normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. D. Not normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. Determine the mean of the sampling distribution of ModifyingAbove p with caret<="" path="">p. mu Subscript ModifyingAbove p with caret Baseline equals <="" path="">p= nothing (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret<="" path="">p. sigma Subscript ModifyingAbove p with caret Baseline equals <="" path="">p= nothing (Round to three decimal places as needed.) QUESTION 14. Suppose a simple random sample of size nequals=7575 is obtained from a population whose size is Upper N equals 30 comma 000N=30,000 and whose population proportion with a specified characteristic is p equals 0.6 .p=0.6. (a) Describe the sampling distribution of ModifyingAbove p with caret<="" path="">p. Choose the phrase that best describes the shape of the sampling distribution below. A. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. B. Not normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. C. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. D. Not normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. Determine the mean of the sampling distribution of ModifyingAbove p with caret<="" path="">p. mu Subscript ModifyingAbove p with caret Baseline equals <="" path="">p= nothing (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret<="" path="">p. sigma Subscript ModifyingAbove p with caret<="" path="">pequals= nothing (Round to six decimal places as needed.) (b) What is the probability of obtaining xequals=5151 or more individuals with the characteristic? That is, what is P(ModifyingAbove p with caret<="" path="">pgreater than or equals0.680.68)? P(ModifyingAbove p with caret<="" path="">pgreater than or equals0.680.68)equals= nothing (Round to four decimal places as needed.) (c) What is the probability of obtaining xequals=3636 or fewer individuals with the characteristic? That is, what is P(ModifyingAbove p with caret<="" path="">pless than or equals0.480.48)? P(ModifyingAbove p with caret<="" path="">pless than or equals0.480.48)equals= nothing (Round to four decimal places as needed.) QUESTION 13. B. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. Determine the mean of the sampling distribution of mu Subscript ModifyingAbove p Mean = np = 800*0.6 = 480.0 Determine the standard deviation of the sampling distribution of Standard deviation = 8000.6(10.6) = 13.856 QUESTION 14. A. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. Determine the mean of the sampling distribution of Mean = np = 75*0.6 = 45 Determine the standard deviation of the sampling distribution Standard deviation = 750.6(10.6) (b) What is the probability of obtaining xequals=51 P(X = 51) = P(Z < 5145 ) 4.24 P(Z < 1.42) = 0.9222 (c) What is the probability of obtaining xequals=36 or fewer individuals with the characteristic? P(X 36.5) = P(Z P(Z -2.00) 36.545 ) 4.24 = 1 - P(Z < 2.00) P(Z < 2.00) = 0.9772 P(Z -2.00) = 0.0228 = 4.24 QUESTION 13. B. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.np(1p)10. Determine the mean of the sampling distribution of mu Subscript ModifyingAbove p Mean = np = 800*0.6 = 480.0 Determine the standard deviation of the sampling distribution of Standard deviation = 8000.6(10.6) = 13.856 QUESTION 14. A. Approximately normal because n less than or equals 0.05 Upper Nn0.05N and np left parenthesis 1 minus p right parenthesis less than 10.np(1p)<10. Determine the mean of the sampling distribution of Mean = np = 75*0.6 = 45 Determine the standard deviation of the sampling distribution Standard deviation = 750.6(10.6) (b) What is the probability of obtaining xequals=51 P(X = 51) = P(Z < 5145 ) 4.24 P(Z < 1.42) = 0.9222 (c) What is the probability of obtaining xequals=36 or fewer individuals with the characteristic? P(X 36.5) = P(Z P(Z -2.00) 36.545 ) 4.24 = 1 - P(Z < 2.00) P(Z < 2.00) = 0.9772 P(Z -2.00) = 0.0228 = 4.24