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In Prolog********. How would I write this? New to using math in prolog. 1. Write the recursive Prolog predicate named myfun/2, where the first argument

In Prolog********. How would I write this? New to using math in prolog.

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1. Write the recursive Prolog predicate named myfun/2, where the first argument is the input of the function below, and the second argument is matched with the output of the function. Use the integer/1 predicate for error checking. f(n)=3,4,f(n1)+2f(n2),n=1n=2n3 For example, ?-myfun(3,R)

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