In Python, must use try/ except blocks

Please comment thought process

classify(input_string): It takes as input a string with a mixed group of integers and words separated by spaces. It returns a tuple of two lists: a list of integers and a list of non-empty words. Use exceptions to distribute words and integers to their respective lists. Note: do NOT include empty string in the return list; any string that does not include an integer only (e.g. '$10' or '3.00) should be classified as words Hint: check what happens when you call int0 on strings like '3.00'. .Parameter: input string: string with a group of integers and words separated by spaces. Return value: a tuple of a list of integers(int) and a list of words(string) Requirement: you must use try-except blocks in your solution! .Examples: O classify("I have 35 apples") O classify("Today is Sunday") o classify( "That will be $1e please") ([35], ['l', 'have', 'apples']) ( [ ] , [ "Today' , ' is ' , ' Sunday' ] ) ([],['That','will", 'be','$10','please']) shelve(inventory, product_list): Given a dictionary, inventory, and a list of tuples product_list, we need to update the inventory with products listed in product_list: if a product is already in store update the amount; if the product is not in store, add a new entry in inventory for it. We might also call this function to update inventory when the stock amount is decreased. But if the amount of any product is below zero, we must raise a ValueError with the "negative amount for product" message Parameters: o inventory:: a dictionary with product name (string) keys and product amount (int) values. o product_list: a list of tuples, each tuple has two members: a string as the product name and an integer as the amount. Returns: None. You should make update to inventory in-place Raises: ValueError when the amount of a product is below zero . Examples: d {"apple" : 50, "pear": 30, "orange" :25) >>> >>> ps("apple", 20), ("pear", -10), ("grape" ,18)] >> shelve(d,ps) pear 20, "grape 18, orange: 25, apple 70) >> shelve(d, [("apple", -1000)]) Traceback (most recent call last): ValueError: negative amount for apple