In six packages of "The Flintstones Real Fruit Snacks" there were seven Bam-Bam snack pieces. The total number of snack pieces the six bags was 67. We wish to calculate a 96% confidence interval for the population proportion of Bam-Bam snack pieces. Part Define the random variables X and P in words OX is the number of Bam-Bam snacks in a sample of 67 snack pieces. Pas the proportion of Bam-Bam pieces in a bag of snacks OX is the proportion of Bam Bam snacks in a bag of snacks. Pis the proportion of Bam-Bam pieces in a sample of 67 snack pieces OX is the proportion of Bam-Bam snacks in a sample of 67 snack pieces Pis the proportion of Bam-Bam pieces in a bag of snacks OX is the number of Bam-Bam snacks in a bag of snacks. Pis the number of BamBam pieces in a sample of 67 snack pieces Part() Which distribution should you use for this problem? (Enter your answer in the form or here is the degrees of freedom.) Explain your choice The Student's distribution should be used because we do not know the standard deviation The Student's distribution should be used because pg 10, which implies a small sample The binomial distribution should be used because the two outcomes are Ban-Ban" and "Not BamBam The standard normal distribution should be used because we are tested in proportions Part() Part 0 Construct a 96% confidence interval for the population proportion of BamBam snack pieces per bag (Round your answers to three decimal places.) () State the confidence interval Sketch the graph J) 002 0.02 (4) Calculate the enior bound Part() (e) Do you think that six packages of frut snacks yield enough data to give accurate results? Why or why not? Yes this is clearly a simple random sample No, we do not know if this sample was obtained from a simple random sample