In the diagram below, the cable is elastic & taut (F-0) and the spring is IS COMPRESSED. The block is AT REST. The acceleration of the block is UP. Ceiling Cable Block Spring Ground Part 4: Applying Newton's 2nd Law For each force listed below, identify which choice BEST REPRESENTS the direction that force is acting on the block. Direction of gravity: ---Select--- Direction of tension: ---Select--- Direction of static friction: ---Select--- Direction of kinetic friction: ---Select--- Direction of normal force: ---Select--- Direction of spring force: ---Select--- Show My Work (Optional) ? Direction of net force: ---Select--- As shown below, a block on a frictionless horizontal surface is attached to a cable and a 202 N/m spring that is stretched 0.3 m. The block is in equilibrium (Fnet = 0). The normal force on the block is 106 N. Determine the block's mass and the tension in the cable. m = FT =