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In the reversible, one-step reaction: The equilibrium constants, in Lmol -1 h -1 , are given by: k = 66 Lmol -1 h -1 k
In the reversible, one-step reaction:
The equilibrium constants, in Lmol-1h-1, are given by:
k = 66 Lmol-1h-1
k' = 97 Lmol-1h-1
The activation energies of the forward reaction (Ea) and the reverse reaction,(Ea '), in kJmol-1, are given by:
Ea = 126 kJmol-1
Ea ' = 113 kJmol-1
a)What is the equilibrium constant of the reaction?
b)Is the reaction endothermic or exothermic?
c) What will be the effect of increasing temperature on the rate constants and the equilibrium constant?
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