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#include #include using namespace std; class Counter { private: int m_count; // counter value int m_stepSize; public: Counter() { m_count = 0; m_stepSize = 1;

#include

#include

using namespace std;

class Counter {

private:

int m_count; // counter value

int m_stepSize;

public:

Counter() { m_count = 0; m_stepSize = 1; }

Counter(int count, int stepSize);

int getCount();

void setCounter(int count, int step);

void getData(int& count, int& stepSize);

void incrementCount(); // increment by 1

void incrementCount(int step);

int getMaxCountValue(int threshold, int step);

static int getTotalCount(Counter* ptr, int numCounter);

};

int main() {

Counter c1(1, 2);

int ctr, ss;

c1.getData(ctr, ss);

cout

cout

cout

c1.incrementCount();

cout

c1.incrementCount(10);

cout

cout

cout

Counter c2;

c2.setCounter(10, 5);

int maxV = 49;

cout

Counter cArray[3];

cArray[0] = Counter(1, 1);

cArray[1] = Counter(5, 5);

cArray[2] = Counter(10, 1);

cout

getchar();

return 0;

}

image text in transcribed

Expected output The c1 counter value =1 The c1 counter step size : 2 Increment count by 2 Updated c1 count value = 3 Increment count by 10 Updated c1 count value = 13 f(k)= 10 + k*5 , find maximum value of f(k) such that f(k)

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