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Initially, 0.660 mol of A is present in a 3.00 L solution. 2 A(aq) = 2 B(aq) + C(aq) At equilibrium, 0.130 mol of C

Initially, 0.660 mol of A is present in a 3.00 L solution. 2 A(aq) = 2 B(aq) + C(aq) At equilibrium, 0.130 mol of C is present. Calculate K. 0.0025 K= Incorrect

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