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Is increasing the temperature of the surroundings the only effect of this lost kinetic energy? If the ground is soft, a hard steel ball

 

Is increasing the temperature of the surroundings the only effect of this "lost" kinetic energy? If the ground is soft, a hard steel ball like this might cause the ground to deform. It does work on the ground while moving. But, once everything comes to a stop we find the kinetic energy just before impact has been converted to thermal energy. The temperature of the affected areas increases, though slightly. Eventually, this thermal energy spreads into the atmosphere and surrounding areas, making any temperature changes undetectable. We might instead drop the ball onto a hard surface. The ball itself might deform or break, and some of the kinetic energy might go into the motion of fragment particles that fly in all directions. But again, in the end, all the kinetic energy is dissipated into thermal energy. What about a case where a ball bounces? Say a rubber ball, with a mass of 0.020 kg, is dropped from rest at a height of 2.75 m. It rebounds off the floor, and reaches a maximum height of 0.963 m before falling again. How much energy (in J) was converted to thermal energy when the ball struck the floor? (Enter the magnitude.)

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