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Jason has an investment of 1,000 that accumulates at a force of interest of 8 = 0.02 +0.004t. Let A be the accumulated value at

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Jason has an investment of 1,000 that accumulates at a force of interest of 8 = 0.02 +0.004t. Let A be the accumulated value at time n, and B be the amount of interest earned during the sixth year. You are given that A + 10B = 1,346.13 2 Determine n. 8 B 10 12

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