Just need to do the variable without the values using python language. thank you in advance

6:59 PM 11% U Mobile Stay Safe 46 INDIVIDUAL ASSIGNMENT BFC 208... INDIVIDUAL ASSIGNMENT BFC 20802 ANALYSIS FOR RESULTANT FORCE Figure 1.0. Resultat force for the truss Figure 1.0 shows a truss with two members marked as member 1-2 and member 2-3. Point and are fixed and Point is a free point. A force of PAN) is subjected at Point downwards. Checking the initial condition The coordinate for each points are stated as M. ..) and Hence Y The length of member 1-2 and member 23 could be obtained by Which the cosine vectors for each member could be concluded as The first procedure is to establish an equilibrium equation for every member force. The scalforce for member 1-2 is denoted as Nand member 2-3 Nos. Here, the equibrium conditionat Point could be considered as Equilibrium on horizontal direction 6:59 PM U Mobile Stay Safe 4G @ 11% INDIVIDUAL ASSIGNMENT BFC 208... cosine vectors for each member could be concluded as B- Bu The first procedure is to establish an equilibrium equation for every member force. The axial force for member 1-2 is denoted as No and member 23 n No More, the equilibrium condition at Point could be considered as Equilibrium on horizontal direction v The equilibrium condition at Point Equilibrium on verion direction It wo solve the simultaneous equations the member forces for every member could be written as Based on the given information, compute the member forces by providing 1) flow chart of pseudocode for the program 2) write the program that consist a coordinate system for each point. 3) apply control structure decision, selection and repetition command in the program. 4) limit the coordinate and is only for positive (+ve) value 5) set the value of N, and to a certain limit INDIVIDUAL ASSIGNMENT BFC 20802 ANALYSIS FOR RESULTANT FORCE (3) Figure 1.0. Resultant force for the truss Figure 1.0 shows a truss with two members, marked as member 1-2 and member 2-3. Point and are fixed and Point is a free point. A force of P (kN) is subjected at Point downwards. Checking the initial condition The coordinate for each points are stated as; (X1. y.). (X2, y2) and (x, y) Hence X12 = X2 Y12 = Y2= The length of member 1-2 and member 2-3 could be obtained by h2 = Which the cosine vectors for each member could be concluded as: (12= B12 = C23 B2 = The first procedure is to establish an equilibrium equation for every member force. The axial force for member 1-2 is denoted as N12 and member 2-3 is N23. Here, the equilibrium condition at Point could be considered as Equilibrium on horizontal direction : N Nis