Kindly answer the following. Thank you.

Consider the general case where the two classes have different means and possibly different variances: X|0=0 N Nmo) X|0=1 N Nutmaf) and the prior distribution of C is P(C'=l) = p P(C=0) 1p. To find the decision boundary, we need to solve the following equation for :r: P(O:U)P(G:0|X:m) :P(C: 1)P(0: 1|sz). It is easier to solve this by first taking the logarithm on both sides. Rearranging the terms, we get: 111[P(C=O)P(X=zc|0=0)] ]n[P(O'= 1)P(X=m|0= 1)] = 0. 1. What is the degree of the equation? Assume 0% 7t 0'? and #0 7b 1.11. O quadratic equation in as. 0 linear equation in at: 0 none of the above 2. Report the coefficient of m2 on the left hand side in the equation above. (If applicable, type mu_O, mu_1 for #0, #1 respectively, sigma_0/\\2 for 0%, and sigma_1/\\2 for 0'21) respectively.) Coefficient of 9:2