last photo has the question I need help with. First three photos are for needed info.

thank you!!

1. Activity Calculations. For each of the following half-cell combinations that you will explore in the Activity, use the Nernst Equation to calculate the expected cell potential (voltage) at 25C. Assume that each half-cell contains an electrode consisting of the pure metal that matches the type of metal ions present in the solution (for example, a half-cell containing copper sulfate would contain a solid copper electrode). The worked example on Page 6 of the Lab 10 Manual will be helpful, as will Table 10-1 on Page 4 of the Lab 10 Manual. Show your work. a. A copper-magnesium (Cu-Mg) voltaic cell that uses 0.5 M CuSO4 and 0.1 MgSO. The standard reduction potentiale Mg + 20 Mg od -2.872 Cu2+28 cm E-tom 2+ since my Land (2) E and lay?) tence my is being oxidized to Myat and cult is being reduced to la Hence the cell reaction will be Ca2+, ze cu foton - My* +24- = Mg E. - 3342 -- Cult + Mg Mget&co The stan Fan 2.372-(-0.38) I 2.2017 The Norut equation is given by 0.0541 Ing at? logo Full o osal log on - 2.309- 2 Eu 3.709 - 06455(-0.699) 62-104-002 OLSS R32 . - 2-127V b. A copper-iron (Cu-Fe) voltaic cell that uses 0.5 M CuSO4 and 0.1 FeSO4 (6) The standard reduction potentials and the el rell reactions are Cu 247 2e Cu L +0.337 V - Fe2++22 Fe =-0.441-3 0-2 Cult+Fe Cat Feet Cu is oxich reduced and te is oxidized flere Eoly +0-337V -(-0.440) Hence the Nest equation- [n-2) 0.737- log [Cult] > 0 774 - 0.02955 x logo -0.477+ 0.020655 -0.7976 = 0.7976V = +0.777V [Fe24] 0.0591 2 log Ecel 0.1 0.5 Econ C. An iron-magnesium (Fe-Mg) voltaic cell that uses 0.1 FeSO4 and 0.1 MgSO4 The alandard reduction potentials and the cell reaction are rag at Mg 24 Pe 24+20 Fe L - 0 4y - 2+ + 20 mg E-3312V - oot + Mg - text Mght | Ecuy = -0,44V - (+2 322) Hence the Nurst equation- TMg24] A log Creat] = 1.922 0.02955 bag of 1982 6.0591 2 1932 - - 1.052 - 0.02255 *(slogo 1932 32 E. cou I Data Table 1 Half-Cell Combination 0.5 M CuSO4 0.1 MgSO4 0.5 M CuSO4 0.1 FeSO4 0.1 Fes/ 0.1 MgSO4 Measured Voltage (V) 2.61 0.68 1.82 b. Compare the values obtained for each half-cell combination above to the values calculated in Problem 1. Discuss two potential sources of error present in the experiment design