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Let f(x) = ln(x^2 - 4x + 8) f^'(x) = ? Can you please 'explain' this thoroughly as I am very lost when it comes
Let f(x) = ln(x^2 - 4x + 8)
f^'(x) = ?
Can you please 'explain' this thoroughly as I am very lost when it comes to natural log (ln) in an equation.
Thank you!
Christine
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