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Let f(x) = ln(x^2 - 4x + 8) f^'(x) = ? Can you please 'explain' this thoroughly as I am very lost when it comes

Let f(x) = ln(x^2 - 4x + 8)

f^'(x) = ?

Can you please 'explain' this thoroughly as I am very lost when it comes to natural log (ln) in an equation.

Thank you!

Christine

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