Let X1, X2, X3, ..., X36 be independent skewed random variables with mean X = 3 and

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Let X1, X2, X3, ..., X36 be independent skewed random variables with mean X = 3 and standard deviation X = 2. Let X be the distribution of the mean of these 36 random variables, namely X =(X_1+X_2++X_36)/36. What is the approximate shape of the distribution of X ? (b) What is the mean of the distribution of X ? (c) What is the standard deviation of the distribution of X ? (d) Can we determine P(X <2.5) using a z-score? You do not need to compute this probability, just answer yes or no and briefly explain why or why not

Posted Date: May 19, 2024 06:20 AM

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Let X1, X2, X3, ..., X36 be independent skewed random variables with mean X = 3 and

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