Liquid food 15% solid (Cp=4.0kJ/kgC) Flow rate 2.6 kg/s at 20 C

Product : Food A Flow rate 0.8 kg/s at 50 C (Cp=3.8 kJ/kgC)

Food B 30% solid (Cp=3.5 kJ/kgC)

Calculate Solid content of A and Flow rate and temperature of B

Indirect heat exchanger use for heat liquid food Find X, m and T Food A 0.8 kg/s Solids content = x 50 C 30% solids Food B Indirect Contact HX 2.6 kg/s 15% solids 20 C Mass flow rate = m Temperature =T 0.03 kg/s steam 125 C condensate water 85C